3x^2+3.6x+0.6=0

Solution for 3x^2+3.6x+0.6=0 equation:

3x^2+3.6x+0.6=0

a = 3; b = 3.6; c = +0.6;
Δ = b2-4ac
Δ = 3.62-4·3·0.6
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.6)-\sqrt{5.76}}{2*3}=\frac{-3.6-\sqrt{5.76}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.6)+\sqrt{5.76}}{2*3}=\frac{-3.6+\sqrt{5.76}}{6}
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